3[g-1]+7=3g+4

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Solution for 3[g-1]+7=3g+4 equation:


Simplifying
3[g + -1] + 7 = 3g + 4

Reorder the terms:
3[-1 + g] + 7 = 3g + 4
[-1 * 3 + g * 3] + 7 = 3g + 4
[-3 + 3g] + 7 = 3g + 4

Reorder the terms:
-3 + 7 + 3g = 3g + 4

Combine like terms: -3 + 7 = 4
4 + 3g = 3g + 4

Reorder the terms:
4 + 3g = 4 + 3g

Add '-4' to each side of the equation.
4 + -4 + 3g = 4 + -4 + 3g

Combine like terms: 4 + -4 = 0
0 + 3g = 4 + -4 + 3g
3g = 4 + -4 + 3g

Combine like terms: 4 + -4 = 0
3g = 0 + 3g
3g = 3g

Add '-3g' to each side of the equation.
3g + -3g = 3g + -3g

Combine like terms: 3g + -3g = 0
0 = 3g + -3g

Combine like terms: 3g + -3g = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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